| Hint | Réponse | % Correct |
|---|---|---|
| U = | RI | 42%
|
| Fel = | qE | 36%
|
| div(B) = | 0 | 29%
|
| ∯E·dS = | Qint/ε0 | 25%
|
| Poids : P = | mg | 20%
|
| div(E) = | ρ/ε0 | 16%
|
| E = | -grad(V) | 12%
|
| Masse molaire : | M=m/n | 12%
|
| ∮B·dl = | μ0Ienlacé | 9%
|
| j = | γE | 8%
|
| Fm = | qv∧B | 7%
|
| Volume molaire : | Vm=V/n | 5%
|
| 3ème loi de Newton | Fb/a=-Fa/b | 4%
|
| -ρfVfg | 4%
| |
| incompressible | 4%
| |
| 2ème loi de newton, Principe fondamentale de la dynamique | ma=F | 4%
|
| parfait | 4%
| |
| Action de support : R = | T+N | 4%
|
| Isochore ⇒Wp = | 0 | 3%
|
| div(v) = | 0 | 3%
|
| rot(v) = | 0 | 3%
|
| Ep = | (1/2)CU² | 3%
|
| Théorème de la puissance cinétique | dEc/dt = Pext+Pint | 3%
|
| Théorème de la puissance mécanique | dEm/dt = Pnc | 3%
|
| fp = | -grad(p) | 3%
|
| Poussée d'Archimède : Π = | -mfg | 3%
|
| stationnaire | 3%
| |
| CoP <(Pompe à chaleur) | 1/(1-Tf/Tc) | 1%
|
| CoP <(Réfrégirateur) | 1/(Tc/Tf-1) | 1%
|
| CoP <(moteur) | 1-Tf/Tc | 1%
|
| Concentration molaire : | Cm=n/V | 1%
|
| Q = | C(V1-V2) | 1%
|
| dp/dz=-ρg | 1%
| |
| γE² | 1%
| |
| Re<2000 | écoulement laminaire | 1%
|
| Re>2000 | écoulement turbulent | 1%
|
| Théorème de l'énergie cinétique | ΔEc = Wext+Wint | 1%
|
| irrotationnel | 1%
| |
| p = | j²/γ | 1%
|
| ϕ = | LI | 1%
|
| Rth = | L/λS | 1%
|
| Quasi statique ⇒ Wp = | -∫p dV | 1%
|
| Wp = | -∫pext dV | 1%
|
| Séch = | Q/T* | 1%
|
| rot(B) = | μ0j+μ0ε0(∂E/∂t) | 0%
|
| Ω = | (1/2)rot(v) | 0%
|
| 1+Qf/Qc | 0%
| |
| Gth = | 1/Rth | 0%
|
| 1/Rth=Σ1/Rthi | 0%
| |
| Xt = | -(1/V)(∂V/∂p)=(1/ρ)(∂ρ/∂p) | 0%
|
| rot(E) = | -∂B/∂t | 0%
|
| S = | Cln(U/Uref) | 0%
|
| uvol = | ρcT | 0%
|
| 1ère Loi de Newton, Principe d'inertie : | Dans un référentiel galiléen, le centre d'inertie de tout point matériel mécaniquement isolé ou pseudo isolé est soit au repos soit en mouvement rectiligne uniforme | 0%
|
| Dm1=Dm2 | 0%
| |
| Pc = | dQc/dt | 0%
|
| dS=(1/T)dU+(P/T)dV-(μ/T)dn | 0%
| |
| Dth=λ/ρc | 0%
| |
| dU=TdS-pdV+μdn | 0%
| |
| Pvisc = | -DvΔPpc | 0%
|
| Pw = | dW/dt | 0%
|
| ΔEm+ΔU=Wnc+Q | 0%
| |
| CoP = | énergie utile/énergie injectée | 0%
|
| Force de frottement fluide : Ff = | -fv | 0%
|
| grad(p)=f | 0%
| |
| Δh+Δem=wu+q | 0%
| |
| Cp = | ∂H/∂T | 0%
|
| H=U+pV | 0%
| |
| I = | ∬j·dS | 0%
|
| ϕth = | ∫∫jth·dS | 0%
|
| jth=-λgrad(T) | 0%
| |
| l1->2=h2-h1 | 0%
| |
| S = | (nR/(γ-1))ln(U/U0)+nRln(V/V0) | 0%
|
| -Pc/Pw | 0%
| |
| Monobare ⇒ Wp = | -pextΔV | 0%
|
| Pf/Pw | 0%
| |
| p+ρgz+(1/2)ρv² | 0%
| |
| p=-∂U/∂V | 0%
| |
| ΔPpc = | -Pvisc/Dv | 0%
|
| -Pw/Pc | 0%
| |
| Séch = | Q1/T1*+Q2/T2* | 0%
|
| CoP =(Pompe à chaleur) | -Qc/W | 0%
|
| CoP =(Réfrégirateur) | Qf/W | 0%
|
| Séch = | ΣQi/Ti* | 0%
|
| Séch = | ∫δQ/T | 0%
|
| Rth=ΣRthi | 0%
| |
| ΔS = | Scrée+Séch | 0%
|
| ΔS=ΔH/T1->2=Δml1->2/T1->2 | 0%
| |
| Rth = | (T1-T2)/ϕth | 0%
|
| ∂ρ/∂t+div(jm)=0 | 0%
| |
| 3D | ∂T/∂t-DthΔ(T)=σth/ρc | 0%
|
| 1D | ∂T/∂t-Dth(∂²T/∂x²)=σth/ρc | 0%
|
| T=∂U/∂S | 0%
| |
| Cv = | ∂U/∂T | 0%
|
| ΔU=W+Q | 0%
| |
| fv = | ηΔv | 0%
|
| Dv = | ∫∫v·dS | 0%
|
| Dm = | ∫∫ρv·dS | 0%
|
| Re = | ρVL/η | 0%
|
| CoP = (Moteur) | -W/Qc | 0%
|
| xv=(v-vL)/(vv-vL)=LM/LV | 0%
|