|
Greatest Prominence
|
Number of "Ultras"
|
Answer
|
|
20,146 ft/ 6,141 m
|
65
|
Alaska
|
|
13,803 ft/ 4,207 m
|
6
|
Hawaii
|
|
13,236 ft/ 4,034 m
|
7
|
Washington
|
|
10,080 ft/ 3,072 m
|
9
|
California
|
|
9,093 ft/ 2,712 m
|
3
|
Colorado
|
|
8,258 ft/ 2,517 m
|
8
|
Nevada
|
|
7,706 ft/ 2,349 m
|
4
|
Oregon
|
|
7,077 ft/ 2,157 m
|
3
|
Wyoming
|
|
|
Greatest Prominence
|
Number of "Ultras"
|
Answer
|
|
6,340 ft / 1,932 m
|
5
|
Arizona
|
|
6,158 ft/ 1,877 m
|
1
|
New Hampshire
|
|
6,138 ft/ 1,938 m
|
8
|
Utah
|
|
6,092 ft/ 1,857 m
|
1
|
North Carolina
|
|
6,002 ft/ 1,829 m
|
3
|
Idaho
|
|
5,719 ft/ 1,743 m
|
4
|
Montana
|
|
5,553 ft/ 1,693 m
|
1
|
New Mexico
|
|
4,919 ft/ 1,499 m
|
0
|
New York
|
|
Volcanoes tend to have high prominences compared to other mountains as they tend to form isolated conical peaks rather than long ridges. A line of gigantic isolated mountains will have a pretty good chance of containing multiple ultras, while a single long ridgeline would probably only have one ultra at the high point of the ridge.
Regarding New York, 1499 m of prominence is close enough that it could actually be an Ultra. Would require either the elevation of Mount Marcy to be measured incorrectly, or the elevation of the low point to a higher peak, likely the Mohawk River Valley, to be off. Either way, when it is literally just a foot or two difference, that is usually within the margin of error.