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States Carried in the 1860 US Election

Name each state carried by the 1860 presidential candidates.
South Carolina did not yet allow a popular vote for presidential candidates.
One state had both a Democrat fusion ticket and a separate Stephen Douglas ticket. This led to the Democrats winning the popular vote in the state, but only the three electors who were on both the fusion ticket and the Douglas ticket winning elector seats. The remaining four seats were won by Republicans. Confusing, I know.
Quiz by DutchessofUlster
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Last updated: September 20, 2022
First submittedSeptember 20, 2022
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Average score39.4%
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Percentage of the vote
State Carried
Winning Candidate
-
South Carolina
Breckinridge
75.86%
Vermont
Lincoln
75.47%
Texas
Breckinridge
63.44%
Minnesota
Lincoln
62.80%
Massachusetts
Lincoln
62.24%
Maine
Lincoln
62.23%
Florida
Breckinridge
61.37%
Rhode Island
Lincoln
59.00%
Mississippi
Breckinridge
57.23%
Michigan
Lincoln
56.90%
New Hampshire
Lincoln
56.59%
Wisconsin
Lincoln
56.26%
Pennsylvania
Lincoln
54.61%
Iowa
Lincoln
54.00%
Alabama
Breckinridge
53.86%
Connecticut
Lincoln
53.71%
New York
Lincoln
Percentage of the vote
State Carried
Winning Candidate
53.06%
Arkansas
Breckinridge
51.90%
New Jersey
Democrat
51.24%
Ohio
Lincoln
51.09%
Indiana
Lincoln
50.69%
Illinois
Lincoln
50.51%
North Carolina
Breckinridge
48.89%
Georgia
Breckinridge
47.72%
Tennessee
Bell
45.93%
Maryland
Breckinridge
45.54%
Delaware
Breckinridge
45.18%
Kentucky
Bell
44.90%
Louisiana
Breckinridge
44.63%
Virginia
Bell
36.20%
Oregon
Lincoln
35.52%
Missouri
Douglas
32.32%
California
Lincoln
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