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Given are some identities of trigonometric multiple Angles. Guess its formula

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Last updated: November 27, 2019

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First submitted | November 27, 2019 |

Times taken | 12 |

Average score | 33.3% |

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1.
Sin*(2θ)*

2 Sin *θ* Cos *θ*
**✓**

2 Sin *θ* 2 Cos *θ*
**✓**

Sin *θ* 2 Cos *θ*
**✓**

Sin 2 *θ* Cos 2 *θ*
**✓**

2.
Cos*(2θ)*

Sin^{2} *θ* - Cos^{2} *θ*
**✓**

Cos^{2} *θ* - Sin^{2} *θ*
**✓**

Sin 2 *θ* - Cos 2 *θ*
**✓**

Cos 2 *θ* - Sin 2 *θ*
**✓**

3.
Tan^{2} *θ*

(1 + Cos *2θ*)/(1 - Cos *2θ*)
**✓**

(Cos^{2} *θ* + 1)/(Cos^{2} *θ* - 1)
**✓**

(1 - Cos *2θ*)/(1 + Cos*2θ*)
**✓**

(Cos^{2} *θ* - 1)/(Cos^{2} *θ* + 1)
**✓**

4.
Sin*(3θ)*

4 Sin*θ* - 3 Sin ^{3}*θ*
**✓**

3 Sin^{3}*θ* - 4 Sin*θ*
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3 Sin*θ* - 4 Sin^{4}*θ*
**✓**

3 Sin*θ* - 4 Sin^{3}*θ*
**✓**

5.
Cos*(3θ)*

4 Cos^{3}*θ* - 3 Cos*θ*
**✓**

3 Cos^{4}*θ* - 4 Cos*θ*
**✓**

4 Cos^{4}*θ* - 3 Cos*θ*
**✓**

3 Cos^{3}*θ* - 4 Cos*θ*
**✓**

6.
Tan*(3θ)*

(2 tan*θ* - tan^{3}*θ*)/(1 - 2 tan^{3}θ)
**✓**

(3 tan*θ* - tan^{3}*θ*)/(3 - 1 tan^{2}θ)
**✓**

(3 tan*θ* - tan^{3}*θ*)/(1 - 3 tan^{2}θ)
**✓**

(3 tan*θ* - tan^{2}*θ*)/(1 - 3 tan^{3}θ)
**✓**

7.
2Cos^{2}*θ*

1 + Cos*(2θ)*
**✓**

Cos*(2θ)* - 1
**✓**

Cos*(2θ)* + 1
**✓**

1 - Cos*(2θ)*
**✓**

8.
2Sin^{2}*θ*

Cos*(2θ)* + 1
**✓**

1 - Cos*(2θ)*
**✓**

1 + Cos*(2θ)*
**✓**

Cos*(2θ)* - 1
**✓**

9.
Tan*(2θ)*

2 tan*θ*/(2 - tan^{2}θ)
**✓**

(2 - tan^{2}θ)/2 tan*θ*
**✓**

2 tan*θ*/(1 - tan^{2}θ)
**✓**

2 tan*θ*/(1 + tan^{2}θ)
**✓**

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